14x-27=3x^2-4x

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Solution for 14x-27=3x^2-4x equation: 



14x-27=3x^2-4x

We move all terms to the left:

14x-27-(3x^2-4x)=0

We get rid of parentheses

-3x^2+14x+4x-27=0

We add all the numbers together, and all the variables

-3x^2+18x-27=0

a = -3; b = 18; c = -27;
Δ = b2-4ac
Δ = 182-4·(-3)·(-27)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-18}{-6}=+3$

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